Question:
At the maximum height of a projectile, the velocity and acceleration are
At the maximum height of a projectile, the velocity and acceleration are
Updated On: Jul 6, 2022
- parallel to each other
- antiparallel to each other
- perpendicular to each other
- inclined to each other at $45^\circ$
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The Correct Option is C
Solution and Explanation
At maximum height ;
$v _{ x }= v _{ x } \cos \theta$ in horizontal direction and $v _{ y }=0$
$
a _{ x }=0, a _{ y }=- g
$
Clearly angle between them is $90^{\circ}$.
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Notes on Motion in a plane
Concepts Used:
Motion in a Plane
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
Equations of Plane Motion
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,
- v = final velocity of the particle
- u = initial velocity of the particle
- s = displacement of the particle
- a = acceleration of the particle
- t = the time interval in which the particle is in consideration