At high pressure and regulated supply of air, methane is heated with catalyst ‘X’ to give methanol and with catalyst ‘Y’ to give methanal. $ X $ and $ Y $ respectively are:

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Step 1: Understanding the Oxidation of Methane   Methane ($ CH_4 $) can be oxidized under controlled conditions to form methanol ($ CH_3OH $) and methanal ($ HCHO $). The choice of catalyst determines the specific oxidation product.  Step 2: Identifying the Catalysts   1. Formation of Methanol ($ CH_3OH $):  - Methane is converted to methanol using copper ($ Cu $) as a catalyst under high pressure. $$ CH_4 + \frac{1}{2} O_2 \xrightarrow{\text{Cu}} CH_3OH $$ 2. Formation of Methanal ($ HCHO $):  - Methane is converted to methanal using molybdenum oxide ($ Mo_2O_3 $) as a catalyst. $$ CH_4 + O_2 \xrightarrow{Mo_2O_3} HCHO + H_2O $$ Step 3: Evaluating the Given Options   - Option (1): Incorrect, as it swaps the catalysts. - Option (2): Correct, as $ Cu $ is used for methanol and $ Mo_2O_3 $ for methanal. - Option (3): Incorrect, as $ V_2O_5 $ and $ KMnO_4 $ are not the catalysts used in this reaction. - Option (4): Incorrect, as $ KMnO_4 $ and $ Cr_2O_3 $ are not the correct catalysts. Thus, the correct answer is  Option (2) .

Answer

$ Mo_2O_3, Cu $

Answer

$ Cu, Mo_2O_3 $

Answer

$ V_2O_5, KMnO_4 $

Answer

$ KMnO_4, Cr_2O_3 $

At high pressure and regulated supply of air, methane is heated with catalyst ‘X’ to give methanol and with catalyst ‘Y’ to give methanal. \( X \) and \( Y \) respectively are:

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The Correct Option is B

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