The latent heat of vaporization of water is given as \( 2256 \times 10^3 \, \text{J/kg} \). To find the internal energy change for 1 g of water:
\[
Q = 2256 \times 10^3 \times \frac{1}{1000} = 2256 \, \text{J}
\]
Thus, the change in internal energy is 2256 J.