Question:

At 345 K, the half life for the decomposition of a sample of a gaseous compound initially at 55.5 kPa was 340 s. When the pressure was 27.8 kPa, the half life was found to be 170 s. The order of the reaction is ________. [integer answer]

Updated On: Jul 21, 2024
Hide Solution
collegedunia
Verified By Collegedunia

Correct Answer: 0

Solution and Explanation

\(t_{\frac{1}{2}}∝\frac{1}{|P_o|^{n-1}}\)

\(\frac{(t_{1/2})_1}{(t_{1/2})}=\frac{|P_0|_2^{n-1}}{|P_0|_1^{n-1}}\)

\(\frac{340}{170}=(\frac{27.8}{55.5})^{n-1}\)

\(2=(\frac{1}{2})^{n-1}\)

2 = (2)1 – n

1 – n = 1

n = 0

Was this answer helpful?
1
0

Questions Asked in JEE Main exam

View More Questions

Concepts Used:

Half-life

The amount of time taken for half of a particular sample to react is known as Half-life.

Half-Life Formula:

We can describe exponential decay by any of the three formulas