\(V_1\), Volume of \(0.2\ g\) \(H_2\) at \(200\ K\)
\(=\frac { 0.2 \times R \times 200}{2 \times P}\)
\(V_2\), Volume of \(3.0\ g\) of gas A at \(300\ K\)
\(= \frac {0.3 \times R \times 300}{M \times P}\)
Given that, \(V_1 = V_2\)
\(⇒ \frac {0.2 \times R \times 200 }{ 2 \times P} = \frac {0.3 \times R \times 300}{M \times P}\)
\(M = 45\) g mol-1
So, the answer is \(45\).
Read More: Some Basic Concepts of Chemistry
There are two ways of classifying the matter:
Matter can exist in three physical states:
Based upon the composition, matter can be divided into two main types: