Since, half life is independent of the initial concentration of \(AB_2\).
Hence, reaction is “First Order”.
\(k =\frac{ 2.303 log\;2}{t_{1/2}}\)
\(\frac{2.303 log\;2}{t_{1/2}} = \frac{2.303}{t} \log\frac{100}{(100−80)}\)
\(\frac{2.303 \times 0.3 }{200} = \frac{2.303 }{ t }\log5\)
\(t = 467 \;s\)
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32
The amount of time taken for half of a particular sample to react is known as Half-life.
We can describe exponential decay by any of the three formulas