2CuSO4(aq) + 2Ag(s) → 2Cu(s) + Ag2SO4(aq)
To predict which reaction cannot occur based on standard electrode potentials, we need to consider the concept of spontaneity in redox reactions. A reaction can spontaneously occur if the standard cell potential, \( E_{\text{cell}}^\circ \), is positive. For a redox reaction: \[ \text{Cell Potential}: E_{\text{cell}}^\circ = E_{\text{cathode}}^\circ - E_{\text{anode}}^\circ \]
The given standard electrode potentials are:
We'll analyze the reactions:
\(\text{CuSO}_4(\text{aq}) + \text{Zn(s)} \to \text{ZnSO}_4(\text{aq}) + \text{Cu(s)}\)
\(\text{CuSO}_4(\text{aq}) + \text{Fe(s)} \to \text{FeSO}_4(\text{aq}) + \text{Cu(s)}\)
\(\text{FeSO}_4(\text{aq}) + \text{Zn(s)} \to \text{ZnSO}_4(\text{aq}) + \text{Fe(s)}\)
\(2\text{CuSO}_4(\text{aq}) + 2\text{Ag(s)} \to 2\text{Cu(s)} + \text{Ag}_2\text{SO}_4(\text{aq})\)
The reaction \( 2\text{CuSO}_4(\text{aq}) + 2\text{Ag(s)} \to 2\text{Cu(s)} + \text{Ag}_2\text{SO}_4(\text{aq}) \) cannot occur spontaneously due to its negative cell potential.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
An electrochemical cell is a device that is used to create electrical energy through the chemical reactions which are involved in it. The electrical energy supplied to electrochemical cells is used to smooth the chemical reactions. In the electrochemical cell, the involved devices have the ability to convert the chemical energy to electrical energy or vice-versa.