To solve this question, let's analyze the assertion and reason provided.
Assertion (A):
[Cr(H2O)6]Cl2 and [Fe(H2O)6]Cl2 are examples of homoleptic complexes.
Reason (R):
All the ligands attached to the metal are the same.
1. Homoleptic Complexes:
Homoleptic complexes are those in which all the ligands attached to the central metal atom or ion are the same. In this case, both [Cr(H2O)6]Cl2 and [Fe(H2O)6]Cl2 have six water molecules (H2O) as ligands, making them homoleptic complexes.
2. Evaluation of Assertion (A):
Both [Cr(H2O)6]Cl2 and [Fe(H2O)6]Cl2 contain the same type of ligand, H2O. Therefore, Assertion (A) is correct.
3. Evaluation of Reason (R):
The reason states that all the ligands attached to the metal are the same, which is true in the case of homoleptic complexes. Therefore, Reason (R) is also correct.
4. Conclusion:
Both the assertion and the reason are correct, and the reason correctly explains the assertion.
Final Answer:
The correct option is that both the assertion and reason are true, and the reason explains the assertion.
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
What is crystal field splitting energy?
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
On the basis of CFT, explain why [Ti(H$_2$O)$_6$]Cl$_3$ complex is coloured? What happens on heating the complex [Ti(H$_2$O)$_6$]Cl$_3$? Give reason.