Given below are two statements:
Statement I: SO\(_2\) and H\(_2\)O both possess V-shaped structures.
Statement II: The bond angle of SO\(_2\) is less than that of H\(_2\)O. In the light of the above statements, choose the most appropriate answer from the options given below:
1. Statement I: Both SO\(_2\) and H\(_2\)O possess V-shaped (bent) structures due to the presence of lone pairs on the central atom. - SO\(_2\): The central sulfur atom forms two double bonds with oxygen and has one lone pair of electrons. - H\(_2\)O: The central oxygen atom forms two single bonds with hydrogen and has two lone pairs of electrons. Thus, this statement is correct.
2. Statement II: The bond angle of SO\(_2\) is approximately 119.5° (sp\(^2\) hybridization), while the bond angle of H\(_2\)O is 104.5° (sp\(^3\) hybridization). - The larger bond angle in SO\(_2\) is due to the greater repulsion caused by the double bonds in SO\(_2\), compared to the single bonds in H\(_2\)O. Thus, this statement is incorrect. \[ \text{SO}_2: \angle \text{O-S-O} \approx 119.5^\circ \quad \text{H}_2\text{O}: \angle \text{H-O-H} \approx 104.5^\circ \]
Conclusion: Statement I is correct, but Statement II is incorrect.
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
Match List-I with List-II: List-I