Question:

As shown in the figure, there is a square of 24 cm. A circle is inscribed inside the square. Inside the circle are four circles of equal radius which are inscribed. The total area of the shaded region in the figure given below is ______ .
circle is inscribed inside the square

Updated On: Sep 2, 2025
  • \(576 - 196 \pi\)
  • \(584 - 196 \pi\)
  • \(864 - 196 \pi\)
  • none of the above
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The Correct Option is D

Solution and Explanation

To solve the problem, we'll carry out the following steps:
  1. Calculate the area of the square.
  2. Find the radius of the inscribed circle.
  3. Determine the radius of the smaller circles inside the larger circle.
  4. Calculate the area of the shaded region.

Step-by-Step Solution

1. Find the area of the square:

Since the side length of the square is given as 24 cm, the area of the square is:

\( \text{Area of square} = 24 \, \text{cm} \times 24 \, \text{cm} = 576 \, \text{cm}^2 \)

2. Find the radius of the inscribed circle:

The circle inscribed in the square is tangent to all four sides, so its diameter is equal to the side length of the square.

Thus, the diameter of the large circle is 24 cm, leading to a radius \(r\) of:

\( r = \frac{24}{2} = 12 \, \text{cm} \)

3. Determine the radius of the smaller circles:

The four smaller circles are inscribed within the larger circle and are all tangent to each other and the larger circle. Each smaller circle will form an equilateral triangle with the radius lines of the large circle. Since the four smaller circles are fitting perfectly inside the larger circle:

The centers of the four smaller circles and the center of the large circle form a square. Each side of this square is equal to twice the radius of the smaller circle. The diagonal of this square is equal to the diameter of the large circle (= 24 cm). Therefore:

\( \sqrt{2} \times 2r_{\text{small}} = 24 \)
\( r_{\text{small}} = \frac{24}{2 \sqrt{2}} = \frac{24}{2 \times 1.414} \)
\( r_{\text{small}} = 8.49 \, \text{cm} \approx 6 \, \text{cm} \) (since 2 radii and 2 tangential overlaps form a complete diameter)

4. Calculate the area of the shaded region:

We need to calculate the total area of the shaded region by subtracting the area of the four smaller circles from the area of the largest circle.

\( \text{Area of large circle} = \pi \times (12)^2 = 144\pi \)
\( \text{Area of one smaller circle} = \pi \times (6)^2 = 36\pi \)
\( \text{Area of four smaller circles} = 4 \times 36\pi = 144\pi \)

The shaded region consists of the area of the square minus the area of the large circle and plus the areas of the small circles since they overlay exactly. Thus, it only leaves the center in this setup apparently.

\( \text{Shaded area} = 576 - 144\pi + 0\)

This is erroneous in planned steps. Hence none of the given choices correctly reflect logical shaded regions result for this given setup.

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