Question:
As shown in the figure, a sector of 30° is removed from a circular disc of mass M and radius R. The moment of inertia of the remaining portion of disc about an axis passing through the centre and perpendicular to plane of disc is
As shown in the figure, a sector of 30° is removed from a circular disc of mass M and radius R. The moment of inertia of the remaining portion of disc about an axis passing through the centre and perpendicular to plane of disc is
Updated On: May 4, 2024
- \(\frac{5}{12}MR^2\)
- \(\frac{17}{2}MR^2\)
- \(\frac{11}{24}MR^2\)
- \(\frac{1}{6}MR^2\)
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The Correct Option is C
Solution and Explanation
The correct option is (C): \(\frac{11}{24}MR^2\)
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