We are given:
Speed in still water \(v = 5 \text{ km/hr}\),
Speed of stream \(u = 2 \text{ km/hr}\),
Additional time taken upstream = 20 minutes = \(\frac{1}{3}\) hours.
The effective speeds are:
Speed Upstream = \(v - u = 5 - 2 = 3 \text{ km/hr}\),
Speed Downstream = \(v + u = 5 + 2 = 7 \text{ km/hr}\).
Let the distance between the two points be \(d \text{ km}\). The time taken for upstream and downstream travel is:
Time Upstream = \(\frac{d}{3}\),
Time Downstream = \(\frac{d}{7}\).
The difference in time between upstream and downstream travel is:
\(\frac{d}{3} - \frac{d}{7} = \frac{1}{3}\).
Simplify the equation:
\(\frac{7d - 3d}{21} = \frac{1}{3}\),
\(\frac{4d}{21} = \frac{1}{3}\).
Multiply through by 21:
\(4d = 7\), \(d = \frac{7}{4} = 1.75 \text{ km}\).
Thus, the distance between the two points is 1.75 km.