Question:

Arrange the following in increasing order of solubility product: \[ {Ca(OH)}_2, {AgBr}, {PbS}, {HgS} \]

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For solubility products, compounds with lower Ksp values are less soluble. Compare Ksp values to determine the order of solubility.
Updated On: Mar 17, 2025
  • HgS<AgBr<PbS<Ca(OH)2
  • PbS<HgS<Ca(OH)2<AgBr
  • Ca(OH)2<AgBr<HgS<PbS
  • HgS<PbS<AgBr<Ca(OH)2
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The Correct Option is C

Solution and Explanation

The solubility product (Ksp) determines how soluble a compound is in water. The larger the Ksp, the more soluble the compound. In this case, we need to compare the solubility products for the compounds.
  • Ca(OH)2 has a relatively high Ksp as it dissociates readily.
  • AgBr has a lower Ksp compared to Ca(OH)2.
  • HgS has an even lower Ksp, meaning it is less soluble than AgBr.
  • PbS has the lowest Ksp among these compounds, making it the least soluble.
Thus, the increasing order of solubility products is: \( {Ca(OH)}_2 <{AgBr} <{HgS} <{PbS} \).
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