Question

Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers: \(Mn = 25; Fe = 26\))
(1) \([FeF_6]^{3–}\)
(2) \([Fe(CN)_6]^{3–}\)
(3) \([MnCl_6]^{3–}\) (high spin)
(4) \([Mn(CN)_6]^{3–}\)

• A. 1 < 2 < 4 < 3
• B. 2 < 4 < 3 < 1
• C. 1 < 3 < 4 < 2
• D. 2 < 4 < 1 < 3

Answer 1

The Correct Option is B

\(Coordination\; Compound\)	\(Number \;of \;unpaired \;e^– (n)\)	\(Magnetic \;moment \;(μ) (B.M)\)
\(A\;[FeF_6]^{3–} – d^5\)	5	5.91
\(B\; [Fe(CN)_6]^{3–} – d^5\)	1	1.73
\(C \;[MnCl_6]^{3–} – d^4\)	4	4.89
\(D\; [Mn(CN)_6]^{3–} – d^4\)	2	2.82

Hence, the correct order of magnetic moment is \(2 < 4 < 3 < 1\)