Question:
Arrange the following compounds in order of increasing
dipole moment, toluene (I), m-dichlorobenzene (II),
o-dichlorobenzene (III),p-dichlorobenzene (IV)
Arrange the following compounds in order of increasing
dipole moment, toluene (I), m-dichlorobenzene (II),
o-dichlorobenzene (III),p-dichlorobenzene (IV)
Updated On: Sep 3, 2023
- I < IV < II < III
- IV < I < II < III
- IV < I < III < II
- IV < II < I < III
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
p-dichlorobenzene is non-polar.
The two dipole vectors cancelling each other giving zero
resultant dipole moment, o-dichlorobenzcne has greater
dipole moment than meta isomer.
Toluene is less polar than both ortho and para
dichlorobenzene. Therefore, the increasing order of dipole
moment is
p-dichlorobenzene < toluene < m-dichlorobenzene
< o-dichlorobenzene
The two dipole vectors cancelling each other giving zero
resultant dipole moment, o-dichlorobenzcne has greater
dipole moment than meta isomer.
Toluene is less polar than both ortho and para
dichlorobenzene. Therefore, the increasing order of dipole
moment is
p-dichlorobenzene < toluene < m-dichlorobenzene
< o-dichlorobenzene
Was this answer helpful?
1
0
Top Questions on Properties of benzene
- Predict the major product in the following reaction:
- CUET (UG) - 2023
- Chemistry
- Properties of benzene
- The total number of all the isomers possible for tribromobenzene is
- WBJEE JENPAS UG - 2023
- Chemistry
- Properties of benzene
Compound B in the above reaction is- CUET (UG) - 2023
- Chemistry
- Properties of benzene
- Match List I with List II.
List-I List-II A. 
I. Br2 in CS2 B. 
II. Na2CR2O7/H2SO4 C. 
III. Zn D. 
IV. CHCl3/NaOH
Choose the correct answer from the options given below:- JEE Main - 2022
- Chemistry
- Properties of benzene
Fig. The stable carbocation formed in the above reaction is
- JEE Main - 2022
- Chemistry
- Properties of benzene
View More Questions
Questions Asked in JEE Advanced exam
- Consider the ellipse \(\frac{x^2}{9}+\frac{y^2}{4}=1\). Let S (p, q) be a point in the first quadrant such that \(\frac{p^2}{9}+\frac{q^2}{4}>1\). Two tangents are drawn from S to the ellipse, of which one meets the ellipse at one end point of the minor axis and the other meets the ellipse at a point T in the fourth quadrant. Let R be the vertex of the ellipse with positive x-coordinate and Obe the center of the ellipse. If the area of the triangle △ORT is \(\frac{3}{2}\) , then which of the following options is correct ?
- JEE Advanced - 2024
- Conic sections
- Among V(CO)6, Cr(CO)5, Cu(CO)3, Mn(CO)5, Fe(CO)5, [Co(CO)3]3-, [Cr(CO)4]4-, and Ir(CO)3, the total number of species isoelectronic with Ni(CO)4 is _________.
[Given, atomic number: V = 23, Cr=24, Mn 25, Fe 26, Co 27, Ni 28, Cu = 29, Ir = 77]- JEE Advanced - 2024
- Isomerism in Coordination Compounds
- Let \(\overrightarrow{OP}=\frac{\alpha-1}{\alpha}\hat{i}+\hat{j}+\hat{k},\overrightarrow{OQ}=\hat{i}+\frac{\beta-1}{\beta}\hat{j}+\hat{k}\) and \(\overrightarrow{OR}=\hat{i}+\hat{j}+\frac{1}{2}\hat{k}\) be three vector where α, β ∈ R - {0} and 0 denotes the origin. If \((\overrightarrow{OP}\times\overrightarrow{OQ}).\overrightarrow{OR}=0\) and the point (α, β, 2) lies on the plane 3x + 3y - z + l = 0, then the value of l is _______.
- JEE Advanced - 2024
- Vector Algebra
- A closed vessel contains 10 g of an ideal gas X at 300 K, which exerts 2 atm pressure. At the same temperature, 80 g of another ideal gas Y is added to it and the pressure becomes 6 atm. The ratio of root mean square velocities of X and Y at 300 K is
- JEE Advanced - 2024
- States of matter
- Let the function \(f:[1,\infin)→\R\) be defined by
\(f(t) = \begin{cases} (-1)^{n+1}2, & \text{if } t=2n-1,n\in\N, \\ \frac{(2n+1-t)}{2}f(2n-1)+\frac{(t-(2n-1))}{2}f(2n+1) & \text{if } 2n-1<t<2n+1,n\in\N. \end{cases}\)
Define \(g(x)=\int\limits_{1}^{x}f(t)dt,x\in(1,\infin).\) Let α denote the number of solutions of the equation g(x) = 0 in the interval (1, 8] and \(β=\lim\limits_{x→1+}\frac{g(x)}{x-1}\). Then the value of α + β is equal to _____.- JEE Advanced - 2024
- Integral Calculus
View More Questions
Concepts Used:
Properties of Benzene
Physical Properties:
- Benzene is a colorless liquid with a distinct odor.
- It's highly flammable and volatile.
- It is soluble in organic solvents while insoluble in water.
- Its boiling point is 80.5°C.
- It shows resonance.
Chemical Properties:
- Nitration: Nitration involves the reaction when benzene is reacted with nitric acid in the presence of sulphuric acid. The temperature then remains at 55°C and it results in the formation of nitrobenzene.
- Sulphonation: Benzene reacts with fuming sulphuric acid and results in the formation of benzene sulfonic acid in sulphonation reactions.
- Halogenation: Benzene reacts with halogen in the presence of the Lewis acid resulting in the formation of aryl halide. This reaction is known as halogenation.
- Friedel Crafts Acylation reaction: During the reaction of the benzene with an acyl halide, in presence of Lewis acid, it results in the formation of acyl benzene. This is called Friedel craft’s acylation reaction.
- Friedel Crafts Alkylation reaction: During the reaction of the benzene with an alkyl halide, in presence of Lewis acid like anhydrous Aluminium Chloride, alkyl benzene is formed. This is called Friedel craft’s alkylation reaction.