The given curve is |x| + |y| = 1. This represents a square centered at the origin (0, 0) with vertices (1,0), (0,1), (-1,0), and (0,-1). The area of the region bounded by this curve can be found by considering the geometry of the figure.
The equation |x| + |y| = 1 defines a square in the coordinate plane. It's necessary to analyze the equations for each segment:
- In the first quadrant where x ≥ 0 and y ≥ 0, the equation is x + y = 1.
- In the second quadrant where x ≤ 0 and y ≥ 0, the equation is -x + y = 1.
- In the third quadrant where x ≤ 0 and y ≤ 0, the equation is -x - y = 1.
- In the fourth quadrant where x ≥ 0 and y ≤ 0, the equation is x - y = 1.
The entire square is symmetric about the x-axis and y-axis. To find the area below the x-axis, integrate over the relevant area below y = 0:
The area in one quadrant of the square is (1/2)*1*1, because it’s a right triangle with legs of length 1.
Since the figure is symmetric about both axes, the total area under the x-axis is \(2 \times \frac{1}{2} \times 1 = 1\).
Thus, the area of the region bounded by the curve |x| + |y| = 1 and the x-axis is 1.
This confirms that the correct answer is: 1