The reaction described in the question involves the formation of a white precipitate with BaCl₂. The formation of a white precipitate with BaCl₂ suggests the presence of sulfate ions (\( \text{SO}_4^{2-} \)), forming barium sulfate (\( \text{BaSO}_4 \)): \[ \text{Ba}^{2+} + \text{SO}_4^{2-} \rightarrow \text{BaSO}_4 \, (\text{white precipitate}) \] Next, the precipitate dissolves in dilute HCl, which releases a gas (B). The fact that this gas decolourises acidified KMnO₄ solution indicates that the gas is sulfur dioxide (SO₂), which is a reducing agent and can reduce potassium permanganate (KMnO₄) to Mn²⁺, decolourising the solution: \[ \text{BaSO}_4 + 2\text{HCl} \rightarrow \text{BaCl}_2 + \text{H}_2\text{SO}_3 \] \[ \text{H}_2\text{SO}_3 \rightarrow \text{SO}_2 + \text{H}_2\text{O} \] Thus, the correct answer is (A), where the salt (A) is BaSO₄ and the gas (B) is SO₂.
When an aqueous solution of salt (A) is mixed with BaCl\(_2\), a dense white precipitate is formed. This indicates that salt (A) contains sulfate ions (SO\(_4^{2-}\)), which react with Ba\(^2+\) ions to form BaSO\(_4\), a white precipitate: \[ \text{Ba}^{2+}(aq) + \text{SO}_4^{2-}(aq) \rightarrow \text{BaSO}_4(s) \] The precipitate of BaSO\(_4\) dissolves in dilute HCl, releasing a gas (B) which is SO\(_2\) (sulfur dioxide). The sulfur dioxide gas decolorizes the purple color of acidified KMnO\(_4\) (potassium permanganate) solution, indicating its reducing nature. Therefore, the gas produced is SO\(_2\), and the salt (A) is BaSO\(_4\). Thus, the correct answer is: \[ \text{BaSO}_4, \text{SO}_2 \]
The graph between variation of resistance of a wire as a function of its diameter keeping other parameters like length and temperature constant is
While determining the coefficient of viscosity of the given liquid, a spherical steel ball sinks by a distance \( x = 0.8 \, \text{m} \). The radius of the ball is \( 2.5 \times 10^{-3} \, \text{m} \). The time taken by the ball to sink in three trials are tabulated as shown:
The group two or alkaline earth metals are s-block elements with two electrons in their s-orbital. They are alkaline earth metals. They are named so because of the alkaline nature of the hydroxides and oxides.
Alkaline earth metals are characterized by two s-electrons. This group of elements includes:
Elements whose atoms have their s-subshell filled with their two valence electrons are called alkaline earth metals. Their general electronic configuration is [Noble gas] ns2. They occupy the second column of the periodic table and so-called as group two metals also.