Comprehension
Answer the questions based on the following table.
| Period/ Product | Mumbai 1993-94 | Kolkata 1993-94 | Delhi 1993-94 | Chennai 1993-94 |
|---|---|---|---|---|
| HD | $20$–$15$ | $35$–$30$ | $20$–$15$ | $20$–$30$ |
| CO | $20$–$25$ | $30$–$15$ | $15$–$10$ | $20$–$15$ |
| BN | $45$–$40$ | $25$–$35$ | $35$–$35$ | $10$–$10$ |
| MT | $15$–$20$ | $10$–$20$ | $10$–$10$ | $50$–$45$ |
Question: 1
The maximum percentage decrease in market share is:
The maximum percentage decrease in market share is:
Show Hint
Always verify if the change is a decrease before computing percentage decrease; increases are ignored in such max-decrease questions.
Updated On: Dec 19, 2025
- 60%
- 50%
- 53.3%
- 20%
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
We compute the percentage decrease for each product in each city:
\[
\text{% Decrease} = \frac{\text{Old share} - \text{New share}}{\text{Old share}} \times 100
\]
Mumbai:
- HD: (20 - 15) / 20 × 100 = 25%
- CO: (20 - 25) → increase (ignore)
- BN: (45 - 40) / 45 × 100 ≈ 11.1%
- MT: (15 - 20) → increase (ignore) Kolkata: - HD: (35 - 30) / 35 × 100 ≈ 14.3%
- CO: (30 - 15) / 30 × 100 = 50%
- BN: (25 - 35) → increase (ignore)
- MT: (10 - 20) → increase (ignore) Delhi: - HD: (20 - 15) / 20 × 100 = 25%
- CO: (15 - 10) / 15 × 100 ≈ 33.3%
- BN: (35 - 35) = 0%
- MT: (10 - 10) = 0% Chennai: - HD: (20 - 30) → increase (ignore)
- CO: (20 - 15) / 20 × 100 = 25%
- BN: (10 - 10) = 0%
- MT: (50 - 45) / 50 × 100 = 10% Maximum decrease found = 50% for CO in Kolkat(a) But we must check for cases where the drop is bigger: none other exceed 50%. Therefore, answer is 50%. Wait — but option says 60%. Recheck: BN in Kolkata: (25 - 35) → actually increased, so ignore. Largest is indeed 50%, so final answer is (b) 50%.
- CO: (20 - 25) → increase (ignore)
- BN: (45 - 40) / 45 × 100 ≈ 11.1%
- MT: (15 - 20) → increase (ignore) Kolkata: - HD: (35 - 30) / 35 × 100 ≈ 14.3%
- CO: (30 - 15) / 30 × 100 = 50%
- BN: (25 - 35) → increase (ignore)
- MT: (10 - 20) → increase (ignore) Delhi: - HD: (20 - 15) / 20 × 100 = 25%
- CO: (15 - 10) / 15 × 100 ≈ 33.3%
- BN: (35 - 35) = 0%
- MT: (10 - 10) = 0% Chennai: - HD: (20 - 30) → increase (ignore)
- CO: (20 - 15) / 20 × 100 = 25%
- BN: (10 - 10) = 0%
- MT: (50 - 45) / 50 × 100 = 10% Maximum decrease found = 50% for CO in Kolkat(a) But we must check for cases where the drop is bigger: none other exceed 50%. Therefore, answer is 50%. Wait — but option says 60%. Recheck: BN in Kolkata: (25 - 35) → actually increased, so ignore. Largest is indeed 50%, so final answer is (b) 50%.
Was this answer helpful?
0
0
Question: 2
The city in which minimum number of products increased their market shares in 1993-94 is:
The city in which minimum number of products increased their market shares in 1993-94 is:
Show Hint
Equality in share is not considered an increase; only strictly higher new values are counte(d)
Updated On: Dec 19, 2025
- Mumbai
- Delhi
- Kolkata
- Chennai
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
We count the number of products with increase in share (new>old):
Mumbai: HD↓, CO↑, BN↓, MT↑ → 2 increases
Kolkata: HD↓, CO↓, BN↑, MT↑ → 2 increases
Delhi: HD↓, CO↓, BN=, MT= → 0 increases
Chennai: HD↑, CO↓, BN=, MT↓ → 1 increase Minimum is 0 (Delhi).
Kolkata: HD↓, CO↓, BN↑, MT↑ → 2 increases
Delhi: HD↓, CO↓, BN=, MT= → 0 increases
Chennai: HD↑, CO↓, BN=, MT↓ → 1 increase Minimum is 0 (Delhi).
Was this answer helpful?
0
0
Question: 3
The market shares of which products did not decrease between 1993-94 in any city?
The market shares of which products did not decrease between 1993-94 in any city?
Show Hint
For “did not decrease” conditions, even one instance of decrease invalidates the product.
Updated On: Dec 19, 2025
- HD
- CO
- BN
- None of these
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
We check each product across 4 cities:
- HD: Mumbai↓, so fails.
- CO: Kolkata↓, so fails.
- BN: Mumbai↓, so fails. Thus, all have at least one city with a decrease.
- CO: Kolkata↓, so fails.
- BN: Mumbai↓, so fails. Thus, all have at least one city with a decrease.
Was this answer helpful?
0
0
Question: 4
The number of products which had 100% market share in four metropolitan cities is:
The number of products which had 100% market share in four metropolitan cities is:
Show Hint
Watch for trick options — 100% share is extreme and usually not present unless explicitly state(d)
Updated On: Dec 19, 2025
- 0
- 1
- 2
- 3
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
100% share means in that city the product has full market, which is not the case in any data row (all values<100). Therefore answer is 0.
Was this answer helpful?
0
0
Question: 5
The number of products which doubled their market shares in one or more cities is:
The number of products which doubled their market shares in one or more cities is:
Show Hint
For “double” checks, remember it’s ≥ 2×, not simply a large percentage increase.
Updated On: Dec 19, 2025
- 0
- 1
- 2
- 3
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Doubling condition: new share ≥ 2 × old share.
- HD: no city meets doubling.
- CO: no city meets doubling.
- BN: no city meets doubling.
- MT: Chennai: 50 → 45 (decrease), so fails doubling. Wait, recheck: doubling means new ≥ 2 × old, so check all cities for MT: Mumbai: 15→20 (not double), Kolkata: 10→20 (double), Delhi: 10→10 (no), Chennai: 50→45 (no). So MT meets condition.
- Another product? Check BN: Kolkata: 25→35 (<50) no. CO: 15→10 no. HD: 20→30 (not double). Thus only 1 product meets condition (MT), so answer is (b) 1.
- HD: no city meets doubling.
- CO: no city meets doubling.
- BN: no city meets doubling.
- MT: Chennai: 50 → 45 (decrease), so fails doubling. Wait, recheck: doubling means new ≥ 2 × old, so check all cities for MT: Mumbai: 15→20 (not double), Kolkata: 10→20 (double), Delhi: 10→10 (no), Chennai: 50→45 (no). So MT meets condition.
- Another product? Check BN: Kolkata: 25→35 (<50) no. CO: 15→10 no. HD: 20→30 (not double). Thus only 1 product meets condition (MT), so answer is (b) 1.
Was this answer helpful?
0
0
Top Questions on Table
- The following table shows the total number of people who were stuck in traffic jam while going to their office on working days of a week due to construction of a flyover. Table also shows the ratio of male to female among them. Find the average number of females who were stuck in traffic on working days.
- Study the following table and answer the question that follows. If the population of state B is 42,00,000 and the population of state C is 32,00,000, then what is the sum of number of females below poverty line in state B and number of males below poverty line in state C?
- The following table shows the total number of people who were stuck in traffic jam while going to their office on working days of a week due to construction of a flyover. Table also shows the ratio of male to female among them. If 30% males on Tuesday and 60% males on Wednesday reached their office on regular time of the office, then how many males got late on Tuesday and Wednesday taken together?
- Study the following table and answer the question that follows. The given table shows the percentage population of three states A, B and C below poverty line and the ratio of males and females as per poverty line. If the total population of state A is 51,00,000, then what is the number of females above the poverty line in state A?
- Four reviewers (R1, R2, R3, R4) are in charge of reviewing products from companies A, B, C, and D. Each reviewer provides a rating between 1 and 5 for the products. Due to a technical glitch, the original ratings were deleted, and only the averages calculated for each product (A, B, C, D) and each reviewer (R1, R2, R3, R4) were saved. The data available is as follows:Tasks:
A B C D Average 3 4 4 ? 4 3 ? 5 ? 4 ? 3 3 ? 4 ? ? ? ? 4.25 4 4 4 4.25
1. What are the missing values in the table?
2. How were the missing values calculated?
3.Verify the correctness of the given averages for both rows and columns.
View More Questions
Questions Asked in CAT exam
- In the set of consecutive odd numbers $\{1, 3, 5, \ldots, 57\}$, there is a number $k$ such that the sum of all the elements less than $k$ is equal to the sum of all the elements greater than $k$. Then, $k$ equals?
- CAT - 2025
- Number Systems
- The number of distinct pairs of integers $(x, y)$ satisfying the inequalities $x>y \ge 3$ and $x + y<14$ is:
- CAT - 2025
- Number Systems
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is:
- CAT - 2025
- Linear Inequalities
- The number of distinct integers $n$ for which $\log_{\left(\frac14\right)(n^2 - 7n + 11)>0$ is:}
- CAT - 2025
- Linear Inequalities
- If $a - 6b + 6c = 4$ and $6a + 3b - 3c = 50$, where $a, b$ and $c$ are real numbers, the value of $2a + 3b - 3c$ is:
- CAT - 2025
- Linear & Quadratic Equations
View More Questions