To solve the problem, we need to explain why Co\(^{2+}\) is easily oxidized to Co\(^{3+}\) in the presence of a strong ligand.
1. Understanding the Oxidation States of Cobalt:
Cobalt (Co) has two common oxidation states: Co\(^{2+}\) and Co\(^{3+}\). Co\(^{2+}\) has a [Ar] 3d⁷ electron configuration, while Co\(^{3+}\) has a [Ar] 3d⁶ electron configuration. Co\(^{3+}\) is more highly charged, making it more electronegative, and it has a greater tendency to attract electrons from its environment.
2. Role of Strong Ligands:
In coordination chemistry, ligands are molecules or ions that surround a metal ion, forming a coordination complex. Strong ligands are those that form stable complexes with metal ions, leading to significant changes in the metal's electronic structure. A strong ligand is a good electron donor, and it stabilizes the metal ion by interacting strongly with it, often leading to oxidation or reduction of the metal ion.
3. Oxidation of Co\(^{2+}\) to Co\(^{3+}\):
Co\(^{2+}\) is more easily oxidized to Co\(^{3+}\) in the presence of a strong ligand because the ligand stabilizes the Co\(^{3+}\) ion. The presence of a strong ligand such as ammonia (NH₃), cyanide (CN⁻), or ethylenediamine (en) creates a stronger field around the metal, which can lower the energy of the Co\(^{3+}\) ion and make its formation more favorable. In the absence of a strong ligand, Co\(^{2+}\) is relatively stable, but the strong ligand induces an oxidation state change by stabilizing the higher oxidation state (Co\(^{3+}\)).
4. Effect of Ligand Field on Oxidation Potential:
The oxidation potential for Co\(^{2+}\) to Co\(^{3+}\) is relatively low in the absence of a strong ligand. However, the presence of a strong ligand increases the stability of Co\(^{3+}\), thus making the oxidation of Co\(^{2+}\) more favorable. This is because strong field ligands cause a large splitting of the metal's d-orbitals, which stabilizes the higher oxidation state and makes the oxidation process energetically more favorable.
5. Final Answer:
Co\(^{2+}\) is easily oxidized to Co\(^{3+}\) in the presence of a strong ligand because the strong ligand stabilizes the Co\(^{3+}\) ion, making the oxidation of Co\(^{2+}\) to Co\(^{3+}\) more thermodynamically favorable.
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
What is crystal field splitting energy?
The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges) on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. In tetrahedral coordination entity formation, the d-orbital splitting is smaller as compared to the octahedral entity.
On the basis of CFT, explain why [Ti(H$_2$O)$_6$]Cl$_3$ complex is coloured? What happens on heating the complex [Ti(H$_2$O)$_6$]Cl$_3$? Give reason.