Aniline does not undergo Friedel-Crafts reaction because 1.(A) It forms salt with the Lewis acid catalyst, AlCl 3 . 2. (B) Nitrogen of aniline acquires negative charge. 3. (C) Nitrogen of aniline acquires positive charge. 4. (D) Nitrogen acts as a strong deactivating group in the further reaction.

Question

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Aniline does not undergo the Friedel-Crafts reaction because the nitrogen atom, being a strong electron-donating group, forms a salt with the Lewis acid catalyst (AlCl 3 ), rendering it inactive for further electrophilic substitution. Additionally, the nitrogen acquires a positive charge,making it strongly deactivating for the reaction.

Answer

(A) It forms salt with the Lewis acid catalyst, AlCl3

Answer

(B) Nitrogen of aniline acquires negative charge

Answer

(C) Nitrogen of aniline acquires positive charge

Answer

(D) Nitrogen acts as a strong deactivating group in the further reaction

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Aniline does not undergo Friedel-Crafts reaction because 1.(A) It forms salt with the Lewis acid catalyst, AlCl₃.
2. (B) Nitrogen of aniline acquires negative charge.
3. (C) Nitrogen of aniline acquires positive charge.
4. (D) Nitrogen acts as a strong deactivating group in the further reaction.

The Correct Option is C

Solution and Explanation

Top Questions on Organic Compounds Containing Nitrogen

Questions Asked in CUET exam

Aniline does not undergo Friedel-Crafts reaction because 1.(A) It forms salt with the Lewis acid catalyst, AlCl3.2. (B) Nitrogen of aniline acquires negative charge.3. (C) Nitrogen of aniline acquires positive charge.4. (D) Nitrogen acts as a strong deactivating group in the further reaction.

The Correct Option is C

Solution and Explanation

Top Questions on Organic Compounds Containing Nitrogen

Questions Asked in CUET exam

Aniline does not undergo Friedel-Crafts reaction because 1.(A) It forms salt with the Lewis acid catalyst, AlCl₃.
2. (B) Nitrogen of aniline acquires negative charge.
3. (C) Nitrogen of aniline acquires positive charge.
4. (D) Nitrogen acts as a strong deactivating group in the further reaction.