Anil can paint a house in 60 days. So, he can do \(\frac{1}{60}\) of work per day.
Bimal can paint it in 84 days. So, he can do \(\frac{1}{84}\) of work per day.
Let’s assume charu can paint it in ‘c’ days. So, he can do \(\frac{1}{c}\) of work per day.
Anil alone does the work for 10 days. So, the work completed is 1616
The remaining work is \(\frac{5}{6}.\)
After that, for 14 days they worked together.
\(\frac{14}{60}+\frac{14}{84}+\frac{14}{c}=\frac{5}{6}.\)
\(\frac{1}{c}= \frac{13}{30}×14\)
Charu does his work for 14 days. So, the total work done by charu is \(\frac{13}{30}\)
The amount earned by charu = \(\frac{13}{30}\times 21000 = Rs 9100\)
Allow the entire task to be W
Anil worked for 24 days now.
For a total of fourteen days, Bimal and Charu worked.
Now that Anil has achieved W in 60 days, he has completed 0.4W in 24 days.
In 84 days, Bimal finishes W.
Therefore, after 14 days, Bimal finishes = \(\frac{W}{6}\);
Consequently,, Charu completes = \(W - \frac{W}{6} - \frac{4W}{10} = \frac{26W}{10} = \frac{13W}{30}\)
hence, Charu's proportion = \(\frac{13}{30} \times 21000 = 9100\)