Angular width of the central maxima in the Fraunhofer diffraction for $\lambda$ = 6000 � is $\theta_{0}$. When the same slit is illuminated by another monochromatic light, the angular width decreases by 30%. The wavelength of this light is,
- 1800 �
- 4200 �
- 6000 �
- 420 �
The Correct Option is B
Solution and Explanation
$\Rightarrow \frac{\theta_{0}}{0.7\theta_{0}} = \frac{\frac{6000\,�}{d}}{\frac{\lambda}{d}} $
$ \Rightarrow \lambda = 4200 \,�$
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Concepts Used:
Single Slit Diffraction
In the single-slit diffraction experiment, we can examine the bending phenomenon of light or diffraction that causes light from a coherent source to hinder itself and produce an extraordinary pattern on the screen called the diffraction pattern.
Read More: Difference Between Diffraction and Interference
Central Maximum
