Question

An organic compound containing phosphorus on oxidation with \( Na_2O_2 \) gives a compound \( X \). When \( X \) is boiled with \( HNO_3 \) and treated with a reagent, it gives a yellow precipitate \( Y \). Identify \( X \) and \( Y \).

• A. \( Na_3PO_4, (NH_4)_2MoO_3 \)
• B. \( Na_3PO_4, (NH_4)_2MoO_4 \)
• C. \( H_3PO_4, (NH_4)_2MoO_4 \)
• D. \( Na_3PO_4, (NH_4)_3PO_4 \cdot 12MoO_3 \)
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Hint:

Phosphorus detection using molybdate test produces a yellow precipitate of ammonium phosphomolybdate.

Answer 1

The Correct Option is D

Step 1: Understanding the Reaction
- Oxidation of phosphorus-containing organic compounds with \( Na_2O_2 \) leads to the formation of \( Na_3PO_4 \) (sodium phosphate).
- Treatment of \( Na_3PO_4 \) with \( HNO_3 \) and ammonium molybdate leads to the formation of yellow precipitate (Y), which is \( (NH_4)_3PO_4 \cdot 12MoO_3 \).
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