An object weighs 200N at the surface of earth. Find the weight at a depth of \(\frac{R}{2}\) , where R is radius of earth
- 100N
- 300N
- 50N
- 150N
The Correct Option is A
Approach Solution - 1
Where, m is the mass of the object and g is acceleration due to gravity on the surface of the earth.
The variation of acceleration due to gravity (g) with the depth (d) from the surface of the Earth is given by
gd=g1-dR
Where
gd is the acceleration due to gravity at depth d
R is the radius of the Earth
At depth d = \(\frac{R}{2}\), acceleration due to gravity is given by
gd=g1-\(\frac{R}{2R}\)=g2
Multiplying both sides by mass of the object, then we get
mgd = \(\frac{mg}{2}\)
But, mg = 200 N
Therefore, Weight of the object at depth R/2 is given by
mgd = \(\frac{200}{2}\) = 100 N
Answer. A
Approach Solution -2
Acceleration due to gravity at depth d from surface of earth
Multiplying by mass 'm' on both sides,
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