To find the kinetic energy (KE) of the object at time \( t = 5 \, \text{s} \), we first need to determine its velocity at that time.
Given:
- Initial velocity (\( v_0 \)) = \( 5 \, \text{m/s} \)
- Acceleration (\( a \)) = \( 1 \, \text{m/s}^2 \)
- Time (\( t \)) = \( 5 \, \text{s} \)
The velocity at any time \( t \) can be found using the equation of motion:
\[ v = v_0 + at \]
Substituting the given values:
\[ v = 5 \, \text{m/s} + (1 \, \text{m/s}^2 \times 5 \, \text{s}) \]
\[ v = 5 \, \text{m/s} + 5 \, \text{m/s} \]
\[ v = 10 \, \text{m/s} \]
Now, we can calculate the kinetic energy at \( t = 5 \, \text{s} \). The kinetic energy (KE) is given by:
\[ KE = \frac{1}{2} m v^2 \]
where \( m \) is the mass of the object. Substituting the given mass (\( m = 1 \, \text{kg} \)) and the calculated velocity (\( v = 10 \, \text{m/s} \)):
\[ KE = \frac{1}{2} \times 1 \, \text{kg} \times (10 \, \text{m/s})^2 \]
\[ KE = \frac{1}{2} \times 1 \times 100 \]
\[ KE = 50 \, \text{J} \]
Therefore, the kinetic energy of the object at time \( t = 5 \, \text{s} \) is \( 50 \, \text{J} \).
Thus Correct Answer is Option 4(D):\(50J\)
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is:
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
Kinetic energy of an object is the measure of the work it does as a result of its motion. Kinetic energy is the type of energy that an object or particle has as a result of its movement. When an object is subjected to a net force, it accelerates and gains kinetic energy as a result. Kinetic energy is a property of a moving object or particle defined by both its mass and its velocity. Any combination of motions is possible, including translation (moving along a route from one spot to another), rotation around an axis, vibration, and any combination of motions.