Step 1: Lens formula
The lens formula is given by:
\[
\frac{1}{f} = \frac{1}{v} - \frac{1}{u}
\]
where:
- \( f \) is the focal length of the lens
- \( v \) is the image distance (positive for real images)
- \( u \) is the object distance (negative for real objects in front of the lens)
Step 2: Substituting the known values
Given:
- Focal length \( f = -20 \, \text{cm} \) (concave lens has a negative focal length)
- Image distance \( v = -30 \, \text{cm} \) (real image)
Substitute in the lens formula:
\[
\frac{1}{-20} = \frac{1}{-30} - \frac{1}{u}
\]
Solving for \( u \):
\[
\frac{1}{u} = \frac{1}{-30} - \frac{1}{-20} = -\frac{1}{60}
\]
Thus, \( u = -60 \, \text{cm} \).
Step 3: Conclusion
Thus, the distance of the object from the lens is \( 40 \, \text{cm} \), hence the correct answer is (A).
Find the unknown frequency if 24 is the median of the following frequency distribution:
\[\begin{array}{|c|c|c|c|c|c|} \hline \text{Class-interval} & 0-10 & 10-20 & 20-30 & 30-40 & 40-50 \\ \hline \text{Frequency} & 5 & 25 & 25 & \text{$p$} & 7 \\ \hline \end{array}\]
Two concentric circles are of radii $8\ \text{cm}$ and $5\ \text{cm}$. Find the length of the chord of the larger circle which touches (is tangent to) the smaller circle.