Question

An isosceles triangular current-carrying loop is kept perpendicularly in a uniform magnetic field \( \vec{B}_0 \) as shown in the figure. The force on the loop due to magnetic field is:

• A. \( ILB_0 \cos \theta \)
• B. \( 2ILB_0 \cos \theta \)
• C. \( 0 \)
• D. \( ILB_0 \sin \theta \)

Hint:

In a uniform magnetic field, a current-carrying closed loop experiences no net force — only torque may act if field is not aligned.

Answer 1

The Correct Option is C

In a uniform magnetic field, the net force on any closed current loop is zero. Each segment may experience a magnetic force, but by symmetry and vector addition, the total force cancels out.
In this case:
- The loop is symmetric.
- Magnetic forces on opposite sides are equal and opposite in direction.
- Thus, net magnetic force on the loop = 0.
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