The inverse demand function is:
\[ P = 230 - Q \]
where total industry output is:
\[ Q = \sum_{i=1}^{6} q_i \]
Each firm \( i \) maximizes its profit:
\[ \pi_i = P \cdot q_i - C(q_i) \]
Given that:
Substituting \( P = 230 - Q \) into the profit equation:
\[ \pi_i = (230 - Q) q_i - 20 q_i \]
Simplify:
\[ \pi_i = (210 - Q) q_i \]
Each firm takes \( Q_{-i} = \sum_{j \neq i} q_j \) as given, so:
\[ Q = q_i + Q_{-i} \]
Substituting this into the profit equation:
\[ \pi_i = (210 - (q_i + Q_{-i})) q_i \]
Differentiate with respect to \( q_i \) and set to zero:
\[ \frac{\partial \pi_i}{\partial q_i} = 210 - 2q_i - Q_{-i} = 0 \]
Rearrange to get the reaction function:
\[ q_i = \frac{210 - Q_{-i}}{2} \]
For \( n = 6 \) identical firms, symmetry implies \( q_i = q_j = q \) for all \( i, j \), and:
\[ Q = 6q \]
Since \( Q_{-i} = 5q \), substitute into the reaction function:
\[ q = \frac{210 - 5q}{2} \]
Solving for \( q \):
\[ 2q = 210 - 5q \]
\[ 7q = 210 \]
\[ q = 30 \]
The total industry output is:
\[ Q = 6q = 6 \times 30 = 180 \]
Substituting \( Q = 180 \) into the inverse demand function:
\[ P = 230 - Q = 230 - 180 = 50 \]
The market price in equilibrium is 50.