Question:

An induced current of 2 A flows through a coil. The resistance of the coil is 10Ω . What is the change in magnetic flux associated with the coil in 1 ms ?

Updated On: Mar 29, 2025
  • 0.2 x10 -2 Wb
  • 2 x10 -2 Wb
  • 22 x10 -2 Wb
  • 0.22 x10 -2 Wb
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The Correct Option is B

Solution and Explanation

Given:

  • Induced current, \( I = 2 \, \text{A} \)
  • Resistance of coil, \( R = 10 \, \Omega \)
  • Time interval, \( \Delta t = 1 \, \text{ms} = 1 \times 10^{-3} \, \text{s} \)
  • Need to find: Change in magnetic flux \( \Delta \Phi \)

Step 1: Use Faraday’s Law of Electromagnetic Induction

\[ \text{Induced emf} \, (\mathcal{E}) = R \cdot I = 10 \times 2 = 20 \, \text{V} \]

Also, emf is related to change in flux by:

\[ \mathcal{E} = \frac{\Delta \Phi}{\Delta t} \Rightarrow \Delta \Phi = \mathcal{E} \cdot \Delta t = 20 \cdot 1 \times 10^{-3} = 20 \times 10^{-3} = 2 \times 10^{-2} \, \text{Wb} \]

The change in magnetic flux is \( {2 \times 10^{-2} \, \text{Wb}} \), so the correct answer is (B).

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