Step 1: Isothermal Expansion.
For an isothermal process, the temperature remains constant, and the gas follows the ideal gas law. The pressure decreases as the volume increases. The final pressure for an isothermal process can be calculated using \( P_{\text{iso}} \).
Step 2: Adiabatic Expansion.
In an adiabatic expansion, there is no heat exchange with the surroundings. As the gas expands, its internal energy decreases, leading to a decrease in temperature. Consequently, for the same volume, the pressure after an adiabatic expansion will be higher than that after an isothermal expansion because the gas has done work on the surroundings. Hence, \( P_{\text{adia}} > P_{\text{iso}} \).
Final Answer: \[ \boxed{\text{(4) } P_{\text{adia}} > P_{\text{iso}}} \]
A hot plate is placed in contact with a cold plate of a different thermal conductivity as shown in the figure. The initial temperature (at time $t = 0$) of the hot plate and cold plate are $T_h$ and $T_c$, respectively. Assume perfect contact between the plates. Which one of the following is an appropriate boundary condition at the surface $S$ for solving the unsteady state, one-dimensional heat conduction equations for the hot plate and cold plate for $t>0$?

The following data is given for a ternary \(ABC\) gas mixture at 12 MPa and 308 K:

\(y_i\): mole fraction of component \(i\) in the gas mixture
\(\hat{\phi}_i\): fugacity coefficient of component \(i\) in the gas mixture at 12 MPa and 308 K
The fugacity of the gas mixture is _________ MPa (rounded off to 3 decimal places).
The internal energy of air in $ 4 \, \text{m} \times 4 \, \text{m} \times 3 \, \text{m} $ sized room at 1 atmospheric pressure will be $ \times 10^6 \, \text{J} $. (Consider air as a diatomic molecule)

