Step 1: Isothermal Expansion.
For an isothermal process, the temperature remains constant, and the gas follows the ideal gas law. The pressure decreases as the volume increases. The final pressure for an isothermal process can be calculated using \( P_{\text{iso}} \).
Step 2: Adiabatic Expansion.
In an adiabatic expansion, there is no heat exchange with the surroundings. As the gas expands, its internal energy decreases, leading to a decrease in temperature. Consequently, for the same volume, the pressure after an adiabatic expansion will be higher than that after an isothermal expansion because the gas has done work on the surroundings. Hence, \( P_{\text{adia}} > P_{\text{iso}} \).
Final Answer: \[ \boxed{\text{(4) } P_{\text{adia}} > P_{\text{iso}}} \]
An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is _____ $ \times 10^{-1} $ J. (Take $ \pi = 3.14 $) 
Match List - I with List - II.

Choose the correct answer from the options given below :