Question:

An alternating current is represented by the equation, $\mathrm{i}=100 \sqrt{2} \sin (100 \pi \mathrm{t})$ ampere. The RMS value of current and the frequency of the given alternating current are

Show Hint

The RMS value of an alternating current is given by the peak value divided by $\sqrt{2}$.
Updated On: Apr 25, 2025
  • $100 \sqrt{2} \mathrm{~A}, 100 \mathrm{~Hz}$
  • $\frac{100}{\sqrt{2}} \mathrm{~A}, 100 \mathrm{~Hz}$
  • $100 \mathrm{~A}, 50 \mathrm{~Hz}$
  • $50 \sqrt{2} \mathrm{~A}, 50 \mathrm{~Hz}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

1. RMS value of current: \[ i_{\text{rms}} = \frac{i_0}{\sqrt{2}} = 100 \mathrm{~A} \]
2. Frequency of the current: \[ f = \frac{\omega}{2\pi} = \frac{100\pi}{2\pi} = 50 \mathrm{~Hz} \] Therefore, the correct answer is (3) $100 \mathrm{~A}, 50 \mathrm{~Hz}$.
Was this answer helpful?
0
0

Questions Asked in JEE Main exam

View More Questions