Step 1: The heating effect of a current is given by \(I_{rms}^2 R\), where \(I_{rms}\) is the root mean square current.
Step 2: For an AC current with a peak value \(I_p = 14.14 A\), \(I_{rms} = \frac{I_p}{\sqrt{2}} = \frac{14.14}{\sqrt{2}} = 10 A\).
Step 3: To achieve the same heating effect with DC, the DC current must equal the RMS value of the AC current.
Step 4: Therefore, the direct current required is 10 A.
The dimension of $ \sqrt{\frac{\mu_0}{\epsilon_0}} $ is equal to that of: (Where $ \mu_0 $ is the vacuum permeability and $ \epsilon_0 $ is the vacuum permittivity)
The unit of $ \sqrt{\frac{2I}{\epsilon_0 c}} $ is: (Where $ I $ is the intensity of an electromagnetic wave, and $ c $ is the speed of light)