Question:

An alkene X (C\(_4\)H\(_8\)) exhibits geometrical isomerism. Oxidation of X with KMnO\(_4\)/H\(^+\) gave Y. On heating sodium salt of Y with a mixture of NaOH and CaO gave Z. What is Z?

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The decarboxylation reaction removes a carbon atom from a carboxylic acid, producing an alkane.
Updated On: Mar 11, 2025
  • CH\(_3\)CH\(_3\)
  • CH\(_3\)CH\(_2\)CH\(_3\)
  • CH\(_3\)CH\(_2\)CH\(_2\)CH\(_3\)
  • CH\(_4\)
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The Correct Option is D

Solution and Explanation

An alkene that exhibits geometrical isomerism must have a carbon-carbon double bond, with each of the two carbons in the double bond attached to two different groups. Of the alkenes with formula C\(_4\)H\(_8\), only 2-butene exhibits geometrical isomerism: \[\text{CH}_3 \text{CH} = \text{CHCH}_3.\]Oxidation of an alkene with KMnO\(_4\)/H\(^+\) cleaves the double bond, and converts each carbon in the double bond to a carbonyl group. Thus, Y is \[\text{CH}_3 \text{COOH}.\]Heating the sodium salt of a carboxylic acid with a mixture of NaOH and CaO produces an alkane with one fewer carbon atom. This reaction is called the decarboxylation reaction. Thus, Z is CH\(_4\).
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