Question

An aircraft of wing span of 60 m flies horizontally in earth's magnetic field of \( 6 \times 10^{-5} \, {T} \) at a speed of 500 m/s. Calculate the e.m.f. induced between the tips of the wings of the aircraft.

Hint:

The induced e.m.f. in a conductor moving through a magnetic field depends on the speed of the conductor, the magnetic field strength, and the length of the conductor.

Answer 1

The e.m.f. induced between the tips of the wings is given by the formula:
\[ \mathcal{E} = B \cdot v \cdot L \] where \( B = 6 \times 10^{-5} \, {T} \) is the magnetic field, \( v = 500 \, {m/s} \) is the speed, and \( L = 60 \, {m} \) is the wingspan of the aircraft. Substituting the values:
\[ \mathcal{E} = 6 \times 10^{-5} \times 500 \times 60 = 1.8 \, {V}. \]