Derive an expression for maximum speed of a vehicle moving along a horizontal circular track.
The maximum speed of a vehicle moving along a horizontal circular track occurs when the centripetal force is equal to the frictional force. The centripetal force \( F_c \) is given by:
\[ F_c = \frac{mv^2}{r} \] where \( m \) is the mass of the vehicle, \( v \) is the velocity, and \( r \) is the radius of the track. The frictional force \( F_f \) is given by:
\[ F_f = \mu mg \] where \( \mu \) is the coefficient of friction and \( g \) is the acceleration due to gravity. Equating the two forces:
\[ \frac{mv^2}{r} = \mu mg \] Solving for \( v \), we get the maximum speed:
\[ v_{{max}} = \sqrt{\mu g r} \]
A sportsman runs around a circular track of radius $ r $ such that he traverses the path ABAB. The distance travelled and displacement, respectively, are:
A body of mass $100 \;g$ is moving in a circular path of radius $2\; m$ on a vertical plane as shown in the figure. The velocity of the body at point A is $10 m/s.$ The ratio of its kinetic energies at point B and C is: (Take acceleration due to gravity as $10 m/s^2$)
Predict the type of cubic lattice of a solid element having edge length of 400 pm and density of 6.25 g/ml.
(Atomic mass of element = 60)
Staying in comfort at home gives one more happiness than travelling.