Aluminium carbide on reaction with \( D_2O \) gives \( Al(OD)_3 \) and ‘X’. What is ‘X’?
Show Hint
- \( C_2D_2 \)
- \( C_3D_4 \)
- \( C_2D_4 \)
- \( CD_4 \)
The Correct Option is D
Solution and Explanation
\[ Al_4C_3 + 12D_2O \rightarrow 4Al(OD)_3 + 3CD_4 \] Step 2: Identify the product
From the reaction, the product \( X \) formed is \( CD_4 \), which is the deuterated methane. Thus, the correct answer is \( CD_4 \).
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