Aluminium carbide on reaction with \( D_2O \) gives \( Al(OD)_3 \) and ‘X’. What is ‘X’?
Show Hint
When carbide reacts with water or heavy water (\( D_2O \)), it forms hydroxide (\( Al(OD)_3 \)) and hydrocarbon products like methane (\( CH_4 \)) or deuterated methane (\( CD_4 \)).
Step 1: Write the reaction
\[
Al_4C_3 + 12D_2O \rightarrow 4Al(OD)_3 + 3CD_4
\]
Step 2: Identify the product
From the reaction, the product \( X \) formed is \( CD_4 \), which is the deuterated methane.
Thus, the correct answer is \( CD_4 \).
Was this answer helpful?
0
0
Top Questions on Law Of Chemical Equilibrium And Equilibrium Constant