Resistance of a wire is \( 8\Omega \). It is drawn in such a way that it experiences a longitudinal strain of \( 400% \). The final resistance of the wire is:
Show Hint
When a wire is stretched uniformly, its resistance changes as \( R' = R (1 + \text{strain})^2 \), where strain is the percentage increase in length.
Step 1: Understanding the Relation Between Resistance and Strain
When a wire is stretched, its resistance changes according to the formula:
\[
R' = R \times (1 + \text{strain})^2
\]
Given that the longitudinal strain is \( 400% \) (or \( 4 \)), the length of the wire increases by a factor of \( 1 + 4 = 5 \). The resistance of a wire is given by:
\[
R' = R \times (5^2)
\]
Step 2: Substituting the Given Values
\[
R' = 8 \times 25 = 200\Omega
\]
Step 3: Conclusion
Thus, the final resistance of the wire is \( \mathbf{200\Omega} \).