Question:

All the diodes in the circuit given below are ideal. Which of the following plots is/are correct when \( V_I \) (in Volts) is swept from \( -M \) to \( M \)?

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In circuits with ideal diodes, the voltage-current relationship shows a sharp transition between regions of zero current (diodes off) and linear current (diodes on).
Updated On: Apr 15, 2025
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The Correct Option is A, D

Solution and Explanation

In the given circuit with ideal diodes, the current-voltage relationship will change depending on the input voltage (\(V_I\)). The behavior of the circuit can be broken down into the following steps: 
Step 1: Diode behavior when \(V_I\) is negative 
When \(V_I\) is negative, the diodes will be reverse biased and no current will flow through the circuit. Therefore, the output voltage \(V_o\) will be 0 for negative \(V_I\), and the plot will be flat from \(-M\) to 0. 
Step 2: Diode behavior when \(V_I\) is positive 
When \(V_I\) is positive, the diodes will conduct and the output voltage will increase linearly with \(V_I\). This results in a linear relationship between \(V_o\) and \(V_I\) for positive \(V_I\). The correct plot is (A) for the output voltage and (D) for the current \(I_I\) in the circuit, where the current increases as \(V_I\) increases.

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