Question:

A positive-edge-triggered sequential circuit is shown below. There are no timing violations in the circuit. Input \( P_0 \) is set to logic ‘0’ and \( P_1 \) is set to logic ‘1’ at all times. The timing diagram of the inputs \( SEL \) and \( S \) are also shown below. The sequence of output \( Y \) from time \( T_0 \) to \( T_3 \) is _________. 

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In sequential circuits with D flip-flops, the output depends on the state changes triggered by the clock edges. Always observe the timing diagram and how the inputs affect the flip-flops' state transitions.
Updated On: Apr 15, 2025
  • 1011
  • 0100
  • 0010
  • 1101
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The Correct Option is A

Solution and Explanation

Step 1: Understand the logic circuit. 
The circuit consists of two D flip-flops \( M_1 \) and \( M_2 \), and the output \( Y \) is determined by the states of these flip-flops. The clock (\( CLK \)) triggers the flip-flops, and the input signals \( SEL \) and \( S \) control the logic transitions. 
Step 2: Analyze the timing diagram. 
Given that \( P_0 = 0 \) and \( P_1 = 1 \), the timing diagram shows how the inputs \( SEL \) and \( S \) evolve over time. These changes determine how the flip-flops' states update, particularly at each rising edge of the clock (\( CLK \)). 
Step 3: Evaluate the output. 
By carefully tracking the state transitions from the timing diagram and understanding the behavior of D flip-flops, the output \( Y \) for times \( T_0 \) to \( T_3 \) is found to be 1011. Thus, the correct answer is (A).

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