In this reaction, cobalt(II) chloride (\( {CoCl}_2 \)) reacts with HCl, forming a dark blue complex. The cobalt ion in the complex is in the \( +2 \) oxidation state, which remains unchanged throughout the reaction. Therefore, statement (B) is correct, as the oxidation state of cobalt does not change in this process.
Regarding the number of unpaired electrons, cobalt(II) in both the complex and the aqueous solution has the same electronic configuration, resulting in the same number of unpaired electrons in both species. Hence, statement (C) is also correct.
The spin-only magnetic moment is a measure of the unpaired electrons in a complex. For \( {Co}^{2+} \) in an octahedral complex with 3 unpaired electrons, the magnetic moment can be calculated using the formula:
\[
\mu_{{sp}} = \sqrt{n(n+2)} \, {BM}
\]
where \( n \) is the number of unpaired electrons. With 3 unpaired electrons, the magnetic moment is approximately 3.87 BM, which confirms that statement (D) is correct.
Thus, the correct answers are (B), (C), and (D).