To solve the problem, we need to determine what product is formed when acidified KMnO4 oxidizes sulphite.
1. Understanding the Reaction:
In an acidic medium, potassium permanganate (KMnO4) is a strong oxidizing agent. It oxidizes sulphite ions (SO32-) to sulphate ions (SO42-).
2. Oxidation of Sulphite:
The sulphite ion (SO32-) gets oxidized by the KMnO4 in the presence of an acidic medium. The manganese in KMnO4 undergoes reduction from +7 oxidation state to +2 oxidation state, forming Mn2+.
3. Balanced Chemical Equation:
The balanced redox reaction in acidic solution is:
2 KMnO4 + 5 SO32- + 4 H2O → 2 Mn2+ + 5 SO42- + 4 OH-
Final Answer:
Acidified KMnO4 oxidizes sulphite (SO32-) to sulphate (SO42-).
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]
Convert Propanoic acid to Ethane

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