To solve the problem, we need to determine what product is formed when acidified KMnO4 oxidizes sulphite.
1. Understanding the Reaction:
In an acidic medium, potassium permanganate (KMnO4) is a strong oxidizing agent. It oxidizes sulphite ions (SO32-) to sulphate ions (SO42-).
2. Oxidation of Sulphite:
The sulphite ion (SO32-) gets oxidized by the KMnO4 in the presence of an acidic medium. The manganese in KMnO4 undergoes reduction from +7 oxidation state to +2 oxidation state, forming Mn2+.
3. Balanced Chemical Equation:
The balanced redox reaction in acidic solution is:
2 KMnO4 + 5 SO32- + 4 H2O → 2 Mn2+ + 5 SO42- + 4 OH-
Final Answer:
Acidified KMnO4 oxidizes sulphite (SO32-) to sulphate (SO42-).
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]
"___ how little changes in the environment can have big repercussions" Tishani Doshi in Journey to the End of the Earth gives an awakening call for man. Analyse the theme of the lesson in the light of the above statement.