In a rhombus, opposite sides are parallel.
If AD has equation $x + y = 1$, then BC is parallel $\Rightarrow$ slope same.
Also BC is opposite and shifted such that origin is midpoint of both diagonals $\Rightarrow$ BC must have same slope and pass through point symmetric to AD w.r.t origin.
Hence intercept is negative of AD’s intercept: $x + y = -1$.
\[
\boxed{x + y = -1}
\]