Question:

ABCD is a rectangle whose vertices are \( A(0,0) \), \( B(8,0) \), \( C(8,6) \), and \( D(0,6) \). Then one of the diagonals of the rectangle is:

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The diagonal of a rectangle with width \( w \) and height \( h \) is: \[ d = \sqrt{w^2 + h^2}. \]
Updated On: Oct 27, 2025
  • \( 12 \)
  • \( 10 \)
  • \( 14 \)
  • \( 16 \)
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The Correct Option is B

Solution and Explanation

The length of the diagonal of a rectangle is given by the distance formula:
\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Using \( A(0,0) \) and \( C(8,6) \): \[ d = \sqrt{(8 - 0)^2 + (6 - 0)^2} \] \[ = \sqrt{64 + 36} = \sqrt{100} = \]
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