A Zener diode of breakdown voltage 10V is used as a voltage regulator as shown in the figure. The current through the Zener diode is
- 50 mA
- 0
- 30 mA
- 20 mA
The Correct Option is C
Solution and Explanation
Calculate Total Current \( I_S \):
The total resistance in the circuit is \( 200\Omega + 500\Omega = 700\Omega \). The source voltage is 20V, so the total current \( I_S \) flowing through the series resistance is:
\[ I_S = \frac{20}{700} = \frac{20}{700} \approx 28.6 \text{ mA} \]
Determine Voltage Across the 500 \( \Omega \) Resistor and Zener Diode:
Since the Zener diode is in breakdown mode (10V across it), the voltage drop across the 500 \( \Omega \) resistor is also 10V. The current \( I_1 \) through the 500 \( \Omega \) resistor is:
\[ I_1 = \frac{10}{500} = 20 \text{ mA} \]
Calculate Current Through the Zener Diode \( I_Z \):
The current \( I_Z \) through the Zener diode is:
\[ I_Z = I_S - I_1 = 28.6 - 20 \approx 30 \text{ mA} \]
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