1.01%
2.01%
1.99%
0.99%
The total resistance \( R_t \), when the voltmeter is connected in parallel with the cell's internal resistance, is given by the parallel resistance formula: \[ R_t = \frac{R_{\text{internal}} \cdot R_{\text{voltmeter}}}{R_{\text{internal}} + R_{\text{voltmeter}}} = \frac{4 \cdot 400}{4 + 400} \approx 3.922 \, \Omega \] The error percentage is then calculated as: \[ \text{Error} = \left(1 - \frac{R_{\text{internal}}}{R_t}\right) \times 100 \approx 0.99\% \]


A battery of emf \( E \) and internal resistance \( r \) is connected to a rheostat. When a current of 2A is drawn from the battery, the potential difference across the rheostat is 5V. The potential difference becomes 4V when a current of 4A is drawn from the battery. Calculate the value of \( E \) and \( r \).

