A vehicle count survey (in Passenger Car Unit) is conducted on a mid-block section of a road at regular intervals of 15 minutes from 8:00 AM to 10:00 AM. Based on the data given in Table below, the Peak Hour Factor (rounded off to two decimal places) for the given survey duration is \(\underline{\hspace{2cm}}\).
Show Hint
The Peak Hour Factor is an important measure of congestion during the peak hours, and is calculated by dividing the maximum volume by the average volume.
The Peak Hour Factor (PHF) is calculated as:
\[
\text{PHF} = \frac{\text{Maximum Volume}}{\text{Average Hourly Volume}}
\]
From the table, the maximum volume occurs from 9:15 AM – 9:30 AM with 405 Passenger Car Units (PCU).
The total volume over the 2-hour period is the sum of all the PCUs:
\[
212 + 248 + 272 + 315 + 337 + 405 + 320 + 267 = 2376\ \text{PCU}
\]
The average hourly volume (AHV) is:
\[
\text{AHV} = \frac{2376}{2} = 1188\ \text{PCU/hour}
\]
Now calculate the PHF:
\[
\text{PHF} = \frac{405}{1188} \approx 0.855
\]
Thus, the Peak Hour Factor is:
\[
\boxed{0.85}
\]
Was this answer helpful?
0
0
Top Questions on Traffic survey methods, Traffic flow Analysis
