Question:
A variable reluctance type tachometer has 60 rotor slots. If the counter records 3600 counts per second, then the speed is:
A variable reluctance type tachometer has 60 rotor slots. If the counter records 3600 counts per second, then the speed is:
Show Hint
To calculate the speed of a tachometer, divide the number of counts per second by the number of rotor slots. This gives the speed in revolutions per minute (rpm).
Updated On: Jun 24, 2025
- 60 rpm
- 360 rpm
- 1800 rpm
- 3600 rpm
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
For a variable reluctance tachometer, the number of rotor slots determines how many counts are recorded per revolution. The speed is calculated by dividing the total number of counts per second by the number of rotor slots.
Given:
- Number of rotor slots = 60
- Counter records 3600 counts per second
The speed is given by: \[ \text{Speed (in rpm)} = \frac{\text{Counter readings per second}}{\text{Number of rotor slots}} = \frac{3600}{60} = 60 \, \text{rpm} \] Thus, the speed of the tachometer is 3600 rpm.
Given:
- Number of rotor slots = 60
- Counter records 3600 counts per second
The speed is given by: \[ \text{Speed (in rpm)} = \frac{\text{Counter readings per second}}{\text{Number of rotor slots}} = \frac{3600}{60} = 60 \, \text{rpm} \] Thus, the speed of the tachometer is 3600 rpm.
Was this answer helpful?
0
0
Top Questions on Electronics
- When testing a coil having a resistance of \( 10\,\Omega \), resonance occurred when the oscillator frequency was \( 10\,\text{MHz} \) and the rotating capacitor was set at \( \dfrac{500}{2\pi}\,\text{pF} \). The effective value of the Q of the coil is:
- The open-loop voltage gain of an amplifier is 240. The noise level in the output without feedback is 100 mV. If a negative feedback with \( \beta = \dfrac{1}{60} \) is used, the noise level in the output will be:
- A differential amplifier has \( R_L = 10\,\text{k}\Omega \) (equal values in both collectors), \( h_{ie} = 1\,\text{k}\Omega \), \( R_e = 50\,\text{k}\Omega \), and \( h_{fe} = 100 \). The common-mode gain is given by:
An op-amp has an offset voltage of 1 mV and is ideal in all other respects. If this op-amp is used in the circuit shown in figure below, the output voltage will be (select the nearest value):
- Which of the following will be the best selection for the core of an LVDT?
View More Questions
Questions Asked in AP PGECET exam
The logic circuit given below converts a binary code \(Y_1, Y_2, Y_3\) into _______.
- AP PGECET - 2025
- Electric circuits and fields
- An ammeter has a current range of 0–5 A, and its internal resistance is 0.2 Ω. In order to change the range to 0–25 A, we need to add a resistance of ________.
- AP PGECET - 2025
- Current Distribution
The bus admittance matrix of the network shown in the given figure, for which the marked parameters are per unit impedance, is _______.
- AP PGECET - 2025
- Electric circuits and fields
- A transformer has a core loss of 64 W and copper loss of 144 W. When it is carrying 20% over load current, the load at which this transformer will operate at the maximum efficiency is _______.
- AP PGECET - 2025
- Current Distribution
- The number of roots of $s^3 + 5s^2 + 7s + 3 = 0$ in the right half of the s-plane is _______.
- AP PGECET - 2025
- Electrical Components
View More Questions