Question:
A uniform solid cylindrical roller of mass '$m$' is being pulled on a horizontal surface with force $F$ parallel to the surface and applied at its centre. If the acceleration of the cylinder is '$a$' and it is rolling without slipping then the value of '$F$' is :
A uniform solid cylindrical roller of mass '$m$' is being pulled on a horizontal surface with force $F$ parallel to the surface and applied at its centre. If the acceleration of the cylinder is '$a$' and it is rolling without slipping then the value of '$F$' is :
Updated On: Sep 27, 2024
- $ma$
- $2\, ma$
- $\frac{3}{2}$ ma
- $\frac{5}{2}$ ma
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The Correct Option is C
Solution and Explanation
$F-f=m a$...(1)
$f^{r}=\left(\frac{m r^{2}}{2}\right)\left(\frac{a}{r}\right)$...(2)
$f=\frac{m a}{2}.$ Therefore, $F=\frac{3 m a}{2}$
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Concepts Used:
System of Particles and Rotational Motion
- The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
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