We know that Power \( P = \frac{2\pi NT}{60} \) where:
- \( P = 2512 \, \text{kW} \)
- \( N = 240 \, \text{rpm} \)
Rearranging the formula for \( T \) (torque), we get:
\[
T = \frac{P \times 60}{2\pi N}
\]
Substituting the values:
\[
T = \frac{2512 \times 60}{2\pi \times 240} \approx 400 \, \text{kN.m}
\]
Thus, the torque in the shaft is approximately 400 kN.m.