Step 1: Understanding the drainage density formula
Drainage density is a measure of the total length of streams per unit area of the watershed. The formula to calculate drainage density (\(D_d\)) is: \[ D_d = \frac{L}{A} \] Where:
\(L\) is the total length of all streams in the watershed (sum of the lengths of streams of all orders),
\(A\) is the area of the watershed.
Step 2: Calculate the total length of streams in each order
1st order streams:
The lengths of the 1st order streams are 3 km, 2.5 km, 4 km, 3 km, 2 km, and 5 km. Total length of 1st order streams = \(3 + 2.5 + 4 + 3 + 2 + 5 = 19.5 \, {km}\). 2nd order streams:
The lengths of the 2nd order streams are 10 km, 15 km, and 7 km. Total length of 2nd order streams = \(10 + 15 + 7 = 32 \, {km}\). 3rd order streams:
The length of the 3rd order stream is 30 km. Total length of 3rd order streams = 30 km.
Step 3: Calculate the total stream length
Total stream length (\(L\)) = Total length of 1st order + Total length of 2nd order + Total length of 3rd order \[ L = 19.5 + 32 + 30 = 81.5 \, {km} \] Step 4: Calculate drainage density
The area of the watershed is 74 km\(^2\). Using the drainage density formula: \[ D_d = \frac{L}{A} = \frac{81.5}{74} \approx 1.10 \, {km/km}^2 \] Step 5: Final answer
The drainage density of the watershed is approximately \(1.10 \, {km/km}^2\).
A particle dispersoid has 1510 spherical particles of uniform density. An air purifier is proposed to be used to remove these particles. The diameter-specific number of particles in the dispersoid, along with the number removal efficiency of the proposed purifier is shown in the following table:
The overall mass removal efficiency of the proposed purifier is ________% (rounded off to one decimal place).
The following table and figure (not to scale) show characteristics of a catchment
The hyetograph resulting from a storm that occurred uniformly over the catchment, is as follows
Assuming a constant base flow of 40 m$^3$/s, the peak of the runoff hydrograph produced by storm for the catchment at the outlet $O$ is ________ m$^3$/s. (rounded off to two decimal places)
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The mean of the posterior distribution is (Answer in integer)
Consider a medium of uniform resistivity with a pair of source and sink electrodes separated by a distance \( L \), as shown in the figure. The fraction of the input current \( (I) \) that flows horizontally \( (I_x) \) across the median plane between depths \( z_1 = \frac{L}{2} \) and \( z_2 = \frac{L\sqrt{3}}{2} \), is given by \( \frac{I_x}{I} = \frac{L}{\pi} \int_{z_1}^{z_2} \frac{dz}{(L^2/4 + z^2)} \). The value of \( \frac{I_x}{I} \) is equal to 
Suppose a mountain at location A is in isostatic equilibrium with a column at location B, which is at sea-level, as shown in the figure. The height of the mountain is 4 km and the thickness of the crust at B is 1 km. Given that the densities of crust and mantle are 2700 kg/m\(^3\) and 3300 kg/m\(^3\), respectively, the thickness of the mountain root (r1) is km. (Answer in integer)
The following table provides the mineral chemistry of a garnet. All oxides are in weight percentage and cations in atoms per formula unit. Total oxygen is taken as 12 based on the ideal garnet formula. Consider Fe as Fetotal and Fe\(^{3+}\) = 0. The Xpyrope of this garnet is _.